Area of a kite: diagonals p and q
[tex]A=\frac{p\times q}{2}[/tex]
a) diagonals: 18in and 5in
[tex]\begin{gathered} A=\frac{18in\times5in}{2} \\ \\ A=\frac{90in^2}{2} \\ \\ A=45in^2 \end{gathered}[/tex]45 square inches
b) diagonals: both square root of 2 cm:
[tex]\begin{gathered} A=\frac{\sqrt[]{2}cm\times\sqrt[]{2}cm}{2} \\ \\ A=\frac{(\sqrt[]{2}cm)^2}{2} \\ \\ A=\frac{2\operatorname{cm}^2}{2} \\ \\ A=1\operatorname{cm}^2 \end{gathered}[/tex]
1 square centimeter
