Hoang has worked as a nurse at Springfield General Hospital for years longer than her friend Bill. Four years ago, she had been at the hospital for twice as long. How long has each been at the hospital?

Respuesta :

Let the number of years Hoang has been in the hospital be H

Let the number of years Bill has been in the hospital be B

The question says Hoang has been in the hospital 6 years longer than Bill.

Mathematically,

H = B + 6 (equation 1)

The question also says 4 years ago, Hoang was at the hospital twice as long as Bill;

4 years ago, Bill's age was = B - 4

4 years ago, Hoang's age was = H - 4

Therefore, we can interprete the statement as:

2 x Bill's age 4 years ago = Hoang's age 4 years ago

Mathematically,

2 x (B - 4) = H - 4

2B - 8 = H - 4

Add 8 to both sides and subtract H from both sides

2B - H = 8 - 4

2B - H = 4 (equation 2)

Substitute the expression for H in equation 1 into equation 2.

2B - H = 4,

But H = B + 6

2B - (B + 6) = 4

2B - B - 6 = 4

Add 6 to both sides

B = 4 + 6 = 10

This means that Bill's years of being in the hospital is 10 years.

Now to find Hoang's years (H),

Using equation 1,

B + 6 = H

But B = 10

10 + 6 = H

H = 16

Thus, Hoang's number of years is 16.

The final answer is: Hoang's number of years = 16, Bill's number of years = 10