The point-slope form of the linear equation is
[tex]y-y_1=m(x-x_1)[/tex]
m is the slope of the line
(x1, y1) is a point on the line
The rule of the slope of the line which passes through points (x1, y1) and (x2, y2) is
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \end{gathered}[/tex]
Since the given line passes through points (1, 4) and (-2, -3), then
[tex]\begin{gathered} (x_1,y_1)=(1,4) \\ (x_{2,}y_2)=(-2,-3) \end{gathered}[/tex]
Substitute them in the rule of the slope to find it
[tex]\begin{gathered} m=\frac{-3-4}{-2-1} \\ m=\frac{-7}{-3} \\ m=\frac{7}{3} \end{gathered}[/tex]
Substitute m and point (1, 4) in the form of the equation above
[tex]y-4=\frac{7}{3}(x-1)[/tex]
But this answer is not in the given choices
The closest answer is b but the value of the slope should be 7/3, not 2
