Respuesta :

Given that Dani has 2000 in a investment account that earns 3% per year compound monthly.

Part A).

The compound interest formula:

Compound interest can be calculated using the formula

[tex]A(t)=P(1+\frac{r}{n})^{nt}[/tex]

where,

A(t) is the account value,

t is measured in years,

P is the starting amount of the account, often called the principal, or more generally present value,

r is the annual percentage rate (APR) expressed as a decimal, and

n is the number of compounding periods in one year.

Now, Part B).

initial amount = 2000

annual percentage rate = 3%

Compounding period = 12

So,

[tex]A(t)=(1+\frac{r}{n})^{nt}[/tex]

Further,

[tex]\begin{gathered} 3500=2000(1+\frac{0.03}{12})^{12t} \\ \frac{3500}{2000}=(1+\frac{0.03}{12})^{12t} \\ \ln 1.75=12t\ln 1.0025 \\ t=\frac{1}{12}\frac{\ln 1.75}{\ln 1.0025} \\ t=18.67 \end{gathered}[/tex]

Hence, t = 18.67 is the answer for part B.