We are given the following expression:
[tex]1^3+2^2+3^1-4^0[/tex]
The first term is 1 elevated to an exponent. Let's remember that 1 to any exponent is always 12, therefore, we have:
[tex]1^3+2^2+3^1-4^0=1+2^2+3^1-4^0[/tex]
Now we solve the second term which is 2 multiply by itself, therefore, we get:
[tex]1+2^2+3^1-4^0=1+4+3^1-4^0[/tex]
The third term is 3 elevated to 1. Let's remember that any number elevated to 1 is the same number, therefore, we get:
[tex]1+4+3^1-4^0=1+4+3-4^0[/tex]
The fourth term is 4 elevated to zero. Let's remember that any number elevated to zero is 1, therefore, we have:
[tex]1+4+3-4^0=1+4+3-1[/tex]
Solving the operations we get:
[tex]1+4+3-1=7[/tex]
Therefore, the expression simplifies to 7.
