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Jason put down a tile floor in his basement. He placed 18 tiles across the floor. Each file is 12 5/8 inches wide. How wide is the area he covered with tiles?

Respuesta :

We solve as follows:

[tex]18\cdot(12\frac{5}{8})=18\cdot(\frac{96}{8}+\frac{5}{8})=18\cdot(\frac{101}{8})=\frac{909}{4}=227.25[/tex]

So, he covered 227.25 inches in width.

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