When 25.0g of Zn reacts, mols of HCl are consumed 0.7648 moles HCl
Write down the balanced chemical equation for this one replacement reaction first.
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)↑⏐
Now take note of the 2:1 mole ratio of reaction between the two reactants. This demonstrates that the reaction will always use up two times as much hydrochloric acid as zinc metal.
As you are aware, a solution's molarity indicates the number of moles of solute—in your case, hydrochloric acid, HCl—that are present in one liter of the solution.
The molarity of the hydrochloric acid solution is reported to be
3.05 mol L−1. This indicates that for every 1 L of solution, 3.05 moles of hydrochloric acid are produced. Remember this for later. You are aware that the reaction needs 25.0 g of zinc.
By using the molar mass of zinc, you can convert this mass to moles.
25 g per mole Zn
65.38g = 3.824 moles of zinc
n order for this many moles of zinc to react, you'd need
0.3824moles Zn⋅2amoles
HCl 1 mole Zn=0.7648 moles HCl
Learn more about reaction here-
https://brainly.com/question/17434463
#SPJ9
