Answer:
[tex]PQ=10\sqrt{2}\:\: \sf units[/tex]
Step-by-step explanation:
Distance between two points formula
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}[/tex]
Define the variables:
- Let (x₁, y₁) = (0, 4)
- Let (x₂, y₂) = (10, -6)
- d = PQ
Substitute the defined variables into the distance formula and solve for PQ:
[tex]\implies PQ=\sqrt{(10-0)^2+(-6-4)^2}[/tex]
[tex]\implies PQ=\sqrt{10^2+(-10)^2}[/tex]
[tex]\implies PQ=\sqrt{100+100}[/tex]
[tex]\implies PQ=\sqrt{200}[/tex]
[tex]\implies PQ=\sqrt{100 \cdot 2}[/tex]
[tex]\implies PQ=\sqrt{100}\sqrt{2}[/tex]
[tex]\implies PQ=10\sqrt{2}\: \sf units[/tex]
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