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Calculate the molarity of a sodium hydroxide solution if 50.0 mL of this solution was completely neutralized by 46.6 mL of 0.750 M sulfuric acid.

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Medunno13

Answer: 0.699 M

Explanation:

[tex]M_{A}V_{A}=M_{B}V_{B}\\(0.750)(46.6)=M_{B}(50.0)\\M_{B}=\frac{0.750)(46.6)}{50.0}=\boxed{0.699 \text{ M}}[/tex]

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