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Analyze the word problem and match the vocabulary terms to the chemicals in the word problem.

5.00 grams of solid citric acid is dissolved in 500.00 ml of water to make aqueous citric acid

Analyze the word problem and match the vocabulary terms to the chemicals in the word problem 500 grams of solid citric acid is dissolved in 50000 ml of water to class=

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5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

What is a solution?

A solution is a homogeneous mixture prepared by dissolving a solute in a solvent.

5.00 grams of solid citric acid is dissolved in 500.00 ml of water to make aqueous citric acid.

In this example:

  • 5.00 grams of solid citric acid is the solute (what is dissolved).
  • 500.00 ml of water is the solvent (the media in which the solute is dissolved).
  • Aqueous citric acid is the resulting solution.

5.00 grams of solid citric acid (solute) is dissolved in 500.00 ml of water (solvent) to make aqueous citric acid (solution).

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