The magnitude of the electric field at the location, where a positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field is 0.25×10⁶ N/C.
The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.
It can be given as,
[tex]E=Fq[/tex]
Here, F is the electric force and q is the charge.
A positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field. Put the values in the fomula,
[tex]E=\dfrac{F}{q}\\E=\dfrac{0.75}{3\times10^{-6}}\\[/tex]
[tex]E=0.25\times10^{6}\rm\; N/C[/tex]
Thus, the magnitude of the electric field at the location, where a positive test charge of 3. 0 μc experiences a force of 0. 75 n in an electric field is 0.25×10⁶ N/C.
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