Respuesta :

zrh2sfo

Answer:

x = 4, y = 2

Step-by-step explanation:

Solve the following system:

{y + x = 6 | (equation 1)

-5 y + 3 x = 2 | (equation 2)

Swap equation 1 with equation 2:

{3 x - 5 y = 2 | (equation 1)

x + y = 6 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{3 x - 5 y = 2 | (equation 1)

0 x + (8 y)/3 = 16/3 | (equation 2)

Multiply equation 2 by 3/8:

{3 x - 5 y = 2 | (equation 1)

0 x + y = 2 | (equation 2)

Add 5 × (equation 2) to equation 1:

{3 x + 0 y = 12 | (equation 1)

0 x + y = 2 | (equation 2)

Divide equation 1 by 3:

{x + 0 y = 4 | (equation 1)

0 x + y = 2 | (equation 2)

Collect results:

Answer: {x = 4, y = 2

Touya03

Step-by-step explanation:

C.) (x,y) = (4,2)

Showing Work:

x+y=6

3x-5y=2

Minus y on both sides

x=6-y

3x-5y=2

Substitute the value of x (which is 6-y) into the second equation

3(6-y)-5y=2

Which ends up being 2

So y=2

Then take the value of y (which is 2) and substitute it into the first equation

x=6-2

x=4

So, like I said,

(x,y) = (4,2)

D.) (x,y) = (9/2, 7)

4x-y=11

6x-2y=13

Then it become:

y=-11+4x

6x-2y=13

Substitute the value of y

6x-2(-11+4x)=13

Which ends up being:

x = 9/2

Then to solve for y just substitute value of x

y= -11+4×9/2

Which is

y=7

So,

(x,y) = (9/2, 7)

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