Answer:
[tex]\displaystyle 55,7[/tex]
Step-by-step explanation:
[tex]\displaystyle 1\frac{41}{53} = sec\:x \hookrightarrow sec^{-1}\:1\frac{41}{53} = x \hookrightarrow 55,678930951...° = x \\ \\ 55,7° ≈ x[/tex]
OR
[tex]\displaystyle \frac{53}{94} = cos\:x \hookrightarrow cos^{-1}\:\frac{53}{94} = x \hookrightarrow 55,678930951...° = x \\ \\ 55,7° ≈ x[/tex]
Information on trigonometric ratios
[tex]\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ[/tex]
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