Answer:
See below
Step-by-step explanation:
[tex]\frac{sin\alpha+tan\alpha}{tan\alpha}[/tex]
[tex]\frac{sin\alpha}{tan\alpha}+\frac{tan\alpha}{tan\alpha}[/tex]
[tex]\frac{sin\alpha}{tan\alpha}+1[/tex]
[tex]\frac{sin\alpha}{\frac{sin\alpha}{cos\alpha}}+1[/tex]
[tex](\frac{sin\alpha}{1}*\frac{cos\alpha}{sin\alpha})+1[/tex]
[tex]cos\alpha+1[/tex]
Hence, [tex]\frac{sin\alpha+tan\alpha}{tan\alpha}=1+cos\alpha[/tex]