The speed at aphelion is mathematically given as
v2 = 21.43 km/s
Question Parameter(s):
At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s.
At aphelion it is 250 x 106 km distant.
Generally, the equation for the angular momentum conservation is mathematically given as
I1*w1 = I2*w2
Therefore
(0.5*m*R1^2)*v1/R1 = (0.5*m*R2^2)*v2/R2
Where
v1*R1 = v2*R2
v2 = v1*(R1/R2) = (30*10^3)*(2.50*10^11)/(3.50*10^11)
v2 = 2.1428*10^4 m/s
v2 = 21.43 km/s
In conclusion, speed is
v2 = 21.43 km/s
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