Given :-
To Find :-
Solution :-
As we know that the standard form of the line is ,
[tex]\sf\longrightarrow[/tex] ax + by + c = 0
So the given equation is ,
[tex]\sf\longrightarrow[/tex] y = 2/5x -1/3
[tex]\sf\longrightarrow[/tex] y = 6x - 5/15
[tex]\sf\longrightarrow[/tex] 15y = 6x - 5
[tex]\sf\longrightarrow[/tex] 6x -15y -5 = 0
Hence the required equation of the line is 6x -15y-5=0.