2Li+(aq)+SO42−(aq)+Sr2+(aq)+2ClO3−(aq) → SrSO4(s)+2Li+(aq)+2ClO3−(aq) The complete ionic equation you determined in Part C is shown above for your convenience. The net ionic equation only depicts the chemical species that participate in the reaction, and that is the formation of a solid between one type of cation and one type of anion in this precipitation reaction. Recall that any of the ions that do not participate in the reaction are spectator ions, and spectator ions are excluded from the net ionic equation. Write the net ionic equation for this precipitation reaction.

Question

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Respuesta :

KimHaChae KimHaChae · Answer 1 · 2021-11-03T09:16:22+01:00

Explanation:

Write a balanced equation, ionic equation and the net ionic equation for the following:

A) Li2SO4 + Sr(NO3)3 --->

B) H2SO4 + Na2CO3 --->

You made a typo: that's Sr(NO3)2

Molecular:

Li2SO4(aq) + Sr(NO3)2(aq) ==> SrSO4(s) + 2LiNO3(aq)

ionic:

2Li^+(aq) + SO4^2-(aq) + Sr^2+(aq) + 2 NO3^-(aq) ==> SrSO4(s) + 2Li^+(aq) + 2NO3^-(aq)

NET ionic:

Just cancel the ions common to both sides to leave you with

Sr^2+(aq) + SO4^2-(aq) ==> SrSO4(s)