3.51 percent of soda cans would have a volume less than 11.8 fl oz.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\Where\ x\ is\ raw \ score,\mu=mean,\sigma=standard\ deviation\\\\\\Given\ that\ \mu=12,\sigma=0.11:For\ x<11.8\\\\z=\frac{11.8-12}{0.11}=-1.81\\\\[/tex]
From the normal distribution table, P(x < 11.8 ) = P(z < -1.81) = 0.0351 = 3.51%
Therefore, 3.51 percent of soda cans would have a volume less than 11.8 fl oz.
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