A motorcycle starts at rest and accelerates at 7 m/s2 for 2 seconds (Δt = 2). After 2 seconds, what is the motorcycle’s velocity in meters per second (m/s)?

A motorcycle starts at rest and accelerates at 7 ms2 for 2 seconds Δt 2 After 2 seconds what is the motorcycles velocity in meters per second ms class=

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Lanuel

The motorcycle’s velocity in meters per second (m/s) is 14.

Given the following data:

  • Initial velocity, U = 0 m/s (since the motorcycle is starting from rest).
  • Time, t = 2 seconds.
  • Acceleration = 7 [tex]m/s^2[/tex]

To find the motorcycle’s velocity in meters per second (m/s), we would use the first equation of motion;

Mathematically, the first equation of motion is given by the formula;

[tex]V = U + at[/tex]

Where:

  • V is the final velocity.
  • U is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]V = 0 + 7(2)\\\\V = 0 + 14[/tex]

Final velocity, V = 14 m/s.

Therefore, the motorcycle’s velocity in meters per second (m/s) is 14.

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