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The foot of a 60 kg sprinter is on the ground for 0.20 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?

Respuesta :

Lanuel

The magnitude of the friction force is 600 Newton.

Given the following data:

  • Mass of sprinter = 60 kg
  • Initial velocity, U = 0 m/s (since the sprinter is starting from rest).
  • Final velocity, V = 0 m/s
  • Time, t = 0.20 seconds.

To find the magnitude of the friction force:

First of all, we would determine the acceleration of the sprinter by using the following formula;

[tex]a = \frac{V \; - \;U}{t}[/tex]

Where:

  • a is the acceleration.
  • V is the final velocity.
  • U is the initial velocity.
  • t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]a = \frac{2 \;- \;0}{0.20} \\\\a = \frac{2}{0.20}[/tex]

Acceleration, a = 10 [tex]m/s^2[/tex]

Now, we would determine the magnitude of the friction force by using Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Force = mass[/tex] × [tex]acceleration[/tex]

[tex]Force = 60[/tex] × [tex]10[/tex]

Force = 600 Newton

Therefore, the magnitude of the friction force is 600 Newton.

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