Respuesta :

Answer:

 

X=5  

Step-by-step explanation:

hope this helps:)

First in ∆KLM

[tex]\\ \sf\longmapsto LM^2=32^2-15^2=992-225[/tex]

[tex]\\ \sf\longmapsto LM^2=767[/tex]

Now

[tex]\\ \sf\longmapsto LM^2=KM\times JM[/tex]

[tex]\\ \sf\longmapsto 767=15(x-15)[/tex]

[tex]\\ \sf\longmapsto 15x-225=767[/tex]

[tex]\\ \sf\longmapsto 15x=767+225=992[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{992}{15}[/tex]

[tex]\\ \sf\longmapsto x=66[/tex]