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which equation represents the general form of a circle with a center at (-2 -3) and a diameter of 8 units ?
• x²+y²+4x+6y-51=0
•x²+y²-4x-6y-51=0
•x²+y²+4x+6y-3=0
•x²+y²-4x-6y-3=0

Respuesta :

Answer:

it’s the 3rd one:)

Step-by-step explanation:

Answer:

  • In this situation, (h, k) = (-2, -3)
  • Radius = 8/2 = 4 units

Substitute them into the circle equation: (x - h)² + (y - k)² = r²

(x - (-2))² + (y - (-3))² = 4²

(x + 2)² + (y + 3)² = 4²

Now expand the equation:

(x + 2)² + (y + 3)² = 4²

(x + 2)(x + 2) + (y + 3)(y + 3) = 16

(x² + 2x + 2x + 4) + (y² + 3y + 3y + 9) = 16

x² + 4x + 4 + y² + 6y + 9 = 16

x² + y² + 4x + 6y + 13 - 16 = 0

x² + y² + 4x + 6y - 3 = 0

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