Respuesta :
Answer:
2y - 3x
Step-by-step explanation:
Given
(2y² - 3xy) ÷ y
Divide each term on the numerator by y , that is
[tex]\frac{2y^2}{y}[/tex] - [tex]\frac{3xy}{y}[/tex] ( cancel y on numerator/ denominator of both fractions )
= 2y - 3x
Answer:
2y - 3x
Step-by-step explanation:
Given
(2y² - 3xy) ÷ y
Divide each term on the numerator by y , that is
[tex]\frac{2y^2}{y}[/tex] - [tex]\frac{3xy}{y}[/tex] ( cancel y on numerator/ denominator of both fractions )
= 2y - 3x