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In electrolysis of sodium chloride, hydrogen and chlorine are liberated from the aqueous sodium chloride solution. Both the gases are transferred into a container which is maintained at 4 atm and 30 ℃. Calculate the volume of the container if 100 mol of H2 and 100 mol of Cl2 are transferred

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Answer:

1.2 × 10³ L

Explanation:

Step 1: Calculate the total number of gaseous moles

n = nH₂ + nCl₂ = 100 mol + 100 mol = 200 mol

Step 2: Convert 30 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30 + 273.15 = 303 K

Step 3: Calculate the volume of the container

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 200 mol × (0.0821 atm.L/mol.K) × 303 K / 4 atm = 1.2 × 10³ L

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