Answer:
the efficiency of the machine is 100%
Explanation:
Given;
load, L = 750 N
length of the lever, L = 2 m
effort applied, E = 250 N
Position of the load from the fulcrum, = 50 cm
50cm
0↓--------------------------Δ-------------------------------↓---------200 cm
750 N x cm 250 N
Apply the principle of moment;
750(50) = 250(x)
x = (750 x 50) / (250)
x = 150 cm
the distance of the effort = 150 cm = 1.5 m
the distance of the load = 50 cm = 0.5 m
The velocity ratio of the machine = 1.5/0.5
= 3
The mechanical advantage of the machine is calculated as;
M.A = Load/effort
M.A = 750 / 250
M.A = 3
The efficiency of the machine is calculated as;
E = (M.A / V.R) x 100%
E = (3/3) x 100% = 100%
Therefore, the efficiency of the machine is 100%
