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In a softball game a batter hits at the velocity of 28 and an angle shown 45 below . What is the maximum range of the ball

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Answer:

80 m

Explanation:

Given :

Initial Velocity, U = 28 m/s

θ = 45°

The maximum range occurs at angle, θ = 45°

The maximum range, R is given by ;

R = U²sin2θ / g

g = acceleration due to gravity = 9.8 m/s²

Plugging in the values :

R = [28² * sin2(45)] / 9.8

R = [28² * sin90] / 9.8

R = 784 / 9.8

R = 80 m