Answer:
[tex]Q=15.7Kw[/tex]
Explanation:
From the question we are told that:
Initial Pressure [tex]P_1=4bar[/tex]
Initial Temperature [tex]T_1=20 C[/tex]
Final Pressure [tex]P_2=12 bar[/tex]
Final Temperature [tex]T_2=80C[/tex]
Work Output [tex]W= 60 kJ/kg[/tex]
Generally Specific Energy from table is
At initial state
[tex]P_1=4bar \& T_1=20 C[/tex]
[tex]E_1=262.96KJ/Kg[/tex]
With
Specific Volume [tex]V'=0.05397m^3/kg[/tex]
At Final state
[tex]P_2=12 bar \& P_2=80C[/tex]
[tex]E_1=310.24KJ/Kg[/tex]
Generally the equation for The Process is mathematically given by
[tex]m_1E_1+w=m_2E_2+Q[/tex]
Assuming Mass to be Equal
[tex]m_1=m_1[/tex]
Where
[tex]m=\frac{V}{V'}[/tex]
[tex]m=frac{0.06666}{V'=0.05397m^3/kg}[/tex]
[tex]m=1.24[/tex]
Therefore
[tex]1.24*262.96+60)=1.24*310.24+Q[/tex]
[tex]Q=15.7Kw[/tex]
