What is the volume of a hemisphere with a radius of 9.8 in, rounded to the nearest
tenth of a cubic inch?
Answer:
3
in
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What is the volume of a hemisphere with the radius of 9.8in , round to the nearest tenth of a cubic

Respuesta :

Answer:

1970.20in³

Explanation:

Formula

[tex] \frac{2}{3} \pi{r}^{3} [/tex]

let's take π as 3.14

[tex] \frac{2}{3} \times 3.14 \times 9.8 \times 9.8 \times 9.8 \\ = \frac{5910.68576}{3} \\= 1970.229 {in}^{3} [/tex]

To the nearest tenth=1970.20in³

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