Answer: [tex]92.18\ m/s[/tex], east
Explanation:
Given
Ship is traveling at a speed of [tex]v=93\ m/s[/tex]
Direction of ship is [tex]25^{\circ}[/tex] North of east
If we break velocity vector in x and y axes then, the horizontal component is given by
[tex]\Rightarrow v_x=93\cos 25^{\circ}\\\Rightarrow v_x=92.18\ m/s[/tex]
The direction of horizontal component is towards east with magnitude of [tex]92.18\ m/s[/tex]
