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2 Na + Cl ---> 2NaCl
how many grams of NaCl can be produced if 33 grams of Na reacts with excess Cl2 and STP?
a. 170 g
b. 120 g
c. 84 g
d. 72 g
If 65 grams is ACTUALLY produced, what is the percent yield of NaCl in the above problem?
a. 54.2%
b. 38.2%
c. 77.4%
d. 90.3%

Respuesta :

jufsanabriasa

Answer:

1. d. 84g

2. c. 77.4%

Explanation:

1. Based on the reaction 2 moles of Na produce 2 moles of NaCl.

The moles of Na (22.99g/mol) in 33g are:

33g * (1mol / 22.99g) = 1.435 moles Na = 1.435 moles NaCl must be produced.

The mass of NaCl is (Molar mass: 58.44g/mol):

1.435moles * (58.44g / mol) = 84g

d. 84g

2. Percent yield is defined as 100 times the ratio between actual yield (65g) and theoretical yield (84g). The percent yield is:

65g / 84g * 100 =

c. 77.4%