Answer: There are 0.854 moles of [tex]Al_{2}(CO_{3})_{3}[/tex] present in 200 g of [tex]Al_{2}(CO_{3})_{3}[/tex].
Explanation:
Given: Mass of [tex]Al_{2}(CO_{3})_{3}[/tex] = 200 g
As number of moles is the mass of substance divided by its molar mass.
Molar mass of [tex]Al_{2}(CO_{3})_{3}[/tex] is 233.99 g/mol.
Therefore, moles of [tex]Al_{2}(CO_{3})_{3}[/tex] is calculated as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{200 g}{233.99 g/mol}\\= 0.854 mol[/tex]
Thus, we can conclude that there are 0.854 moles of [tex]Al_{2}(CO_{3})_{3}[/tex] present in 200 g of [tex]Al_{2}(CO_{3})_{3}[/tex].
