Answer:
The right answer is "74.516 kPa".
Explanation:
The given values are:
V₁ = 21.5 L
V₂ = 32.6L
P₁ = 107 kPa
T₁ =27.2°C+273
T₂ = 44.1 °C+273
As we know,
⇒ [tex]\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}[/tex]
then,
⇒ [tex]P_2=\frac{P_1V_1T_2}{T_1V_2}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{107\times 21.5\times (44.1+273)}{(27.2+273)\times 32.6}[/tex]
⇒ [tex]=\frac{107\times 21.5\times 317}{300.2\times 32.6}[/tex]
⇒ [tex]=\frac{729258.5}{9786.52}[/tex]
⇒ [tex]=74.516 \ kPa[/tex]
