A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?
Answer: 0.110 L
Explanation:
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock silver nitrate solution = 1.82 M
[tex]V_1[/tex] = volume of stock silver nitrate solution = ?
[tex]M_1[/tex] = molarity of diluted silver nitrate solution = 1.00 M
[tex]V_1[/tex] = volume of diluted silver nitrate solution = 0.200 L
Putting in the values we get:
[tex]1.82M\times V_1=1.00M\times 0.200L[/tex]
[tex]V_1=0.110L[/tex]
Therefore, volume of silver nitrate stock solution required is 0.110 L