9514 1404 393
Answer:
Step-by-step explanation:
10 years ago, the sum of their ages was 65 -2·10 = 45.
If Karl was twice as old as Eddie, his contribution was 2/3 of the sum and Eddie's was 1/3. That is, Karl was (2/3)(45) = 30 and Eddie was 15 at that time.
Now, Karl is 40 and Eddie is 25.
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This can be solved using a system of equations.
e = 65 -k
(k -10) = 2(e -10)
Substituting the first equation into the second gives ...
k -10 = 2((65 -k) -10)
k -10 = 110 -2k . . . . . . . simplify
3k = 120 . . . . . . . . . . . . add 10+2k
k = 40
e = 65 -40 = 25
