Respuesta :

leena

Hi there!

[tex]\large\boxed{\text{p(x) = 4(3)^{x}, q(x) = 4(2)^{x}}}[/tex][tex]\large\boxed{p(x) = 4(3)^{x}}}\\\large\boxed{ q(x) = 4(2)^{x}}[/tex]

(a)

Looking at the graphs, we see that both p(x) and q(x) intersect the y-axis at

y = 4, or (0, 4).

(b)

The base of the functions is simply the value of the y-intercept, or a = 4.

(c)

We can write equations for both using an external point at x = 1:

p(x):

y = 4(b)^x

Plug in the point (1, 12) to solve:

12 = 4(b)^1

12 = 4b

b = 3

Rewrite the equation:

[tex]p(x) = 4(3)^{x}[/tex]

q(x):

y = 4(b)^x, plug in the point (1, 8):

8 = 4(b)^1

8 = 4b

b = 2

Rewrite:

[tex]q(x) = 4(2)^{x}[/tex]