Answer:
[tex] \huge \boxed{ \boxed{ \red{ \tt17 \: mph}}}[/tex]
Step-by-step explanation:
to understand this
you need to know about:
- equation
- equation word problems
- PEMDAS
given:
- Miguel can drive 4 times as fast as Raul can ride his bicycle. If it takes Raul 3 hours longer than Miguel to travel 68 miles, how fast (in mph) can Raul ride his bicycle
tips and formulas:
to find
- how fast can Raul ride his bicycle
let's solve:
let's the speed of Raul be x
likewise
Miguel can drive 4 times as fast as Raul can ride his bicycle
therefore
4x
according to the question
[tex] \sf \frac{68}{4x}+3=\frac{68}{x}[/tex]
[tex] \implies \sf \frac{68 + 12x}{4x} = \frac{68}{x} [/tex]
[tex] \sf factor \: out \: 4 \: and \: reduce \: it : \\ \sf \implies \frac{4(17 + 3x)}{4x} = \frac{68}{x} \\ \\ \implies\sf \frac{17 + 3x}{x} = \frac{68}{x}[/tex]
[tex] \sf multipy \: both \: sides \: by \: x : \\ \sf \implies (\frac{17 +3 x}{x} )x = (\frac{68}{x} )x \\ \implies \sf 17 + 3x = 68[/tex]
[tex] \sf cancel \: 17 \: from \: both \: sides : \\ \implies \sf 17 - 17 + 3x = 68 - 17 \\ \implies \sf 3x = 51[/tex]
[tex] \sf divide \: both \: side s \: by \: 3 : \\ \sf \implies \frac{3x}{3} = \frac{51}{3} \\ \therefore x = 17[/tex]
