Answer:
0.74s
Explanation:
Given parameters:
Vertical height of Jump = 2.7m
Unknown:
Time of suspension in air = ?
Solution:
To solve this problem, we have to use one of the kinematics equation.
H = ut + [tex]\frac{1}{2}[/tex] g t²
H is the height
u is the initial velocity
t is the time
g is the acceleration due gravity
U = 0m/s
So;
H = [tex]\frac{1}{2}[/tex] g t² = [tex]\frac{1}{2}[/tex] x 9.8 x t²
2.7 = 4.9t²
t² = 0.55
t = 0.74s
