Answer:
1.6283 × 10²⁴ atoms Ni
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
Explanation:
Step 1: Define
158.69 g Ni
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Ni - 58.69 g/mol
Step 3: Convert
- Set up: [tex]\displaystyle 158.69 \ g \ Ni(\frac{1 \ mol \ Ni}{58.69 \ g \ Ni})(\frac{6.022 \cdot 10^{23} \ atoms \ Ni}{1 \ mol \ Ni})[/tex]
- Multiply/Divide: [tex]\displaystyle 1.62827 \cdot 10^{24} \ atoms \ Ni[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 5 sig figs.
1.62827 × 10²⁴ atoms Ni ≈ 1.6283 × 10²⁴ atoms Ni
