Answer:
[tex]m=\frac{1}{4}[/tex]
Step-by-step explanation:
Given
[tex]y+2=\frac{1}{4}(x-3)[/tex]
Required
Find the slope
[tex]y+2=\frac{1}{4}(x-3)[/tex]
Subtract 2 from both sides
[tex]y+2-2=\frac{1}{4}(x-3) - 2[/tex]
[tex]y=\frac{1}{4}(x-3) - 2[/tex]
Open bracket
[tex]y=\frac{1}{4}x-\frac{1}{4}*3 - 2[/tex]
[tex]y=\frac{1}{4}x-\frac{3}{4} - 2[/tex]
Take LCM
[tex]y=\frac{1}{4}x+\frac{-3 - 8}{4}[/tex]
[tex]y=\frac{1}{4}x+\frac{-11}{4}[/tex]
[tex]y=\frac{1}{4}x-\frac{11}{4}[/tex]
An equation has the form:
[tex]y = mx + b[/tex]
Where
[tex]m = slope[/tex]
By comparing: [tex]y = mx + b[/tex] and [tex]y=\frac{1}{4}x-\frac{11}{4}[/tex]
[tex]m=\frac{1}{4}[/tex]
So, the slope is 1/4
