Answer:
Angular acceleration, [tex]\alpha =0.64\ rad/s^2[/tex]
Explanation:
Given that,
Initial angular velocity, [tex]\omega_i=4.67\ rad/s[/tex]
The final angular velocity, [tex]\omega_f=7.37\ rad/s[/tex]
Time, t = 4.2 s
We need to find her average angular acceleration during this time interval. Acceleration is the rate of change of velocity. So,
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{7.37-4.67}{4.2}\\\\\alpha =0.64\ rad/s^2[/tex]
So, her average angular acceleration is [tex]0.64\ rad/s^2[/tex].
