Answer:
the left over piece is [tex]11 \frac{4}{5}[/tex] inches
Step-by-step explanation:
The computation is shown below:
The total length of the strips is
[tex]= 11 \frac{3}{5} + 15 \frac{1}{5} + 9 \frac{2}{3} \\\\= \frac{58}{5} + \frac{76}{5} + \frac{47}{5}\\\\= \frac{58 + 76 + 47}{5}\\\\= \frac{181}{5}\\\\= 36 \frac{1}{5}[/tex]
The left over piece would be
[tex]= 48 - 36 \frac{1}{5}\\\\= 48 - \frac{181}{5}\\\\= \frac{240 - 181}{5}\\\\= \frac{59}{5}\\\\= 11 \frac{4}{5}[/tex]
Hence, the left over piece is [tex]11 \frac{4}{5}[/tex] inches
