Answer:
Mass = 40 g
Explanation:
Given data:
Mass of oxygen needed = ?
Mass of propane = 11 g
Solution:
Chemical equation:
C₃H₈ +5O₂ → 3CO₂ + 4H₂O
Number of moles of propane:
Number of moles = mass/molar mass
Number of moles = 11 g/ 44.1 g/mol
Number of moles = 0.25 mol
now we will compare the moles of propane and oxygen.
C₃H₈ : O₂
1 : 5
0.25 : 5/1×0.25 = 1.25 mol
Mass of oxygen needed:
Mass = number of moles × molar mass
Mass = 1.25 mol × 32 g/mol
Mass = 40 g
