Answer:
768 numbers
Step-by-step explanation:
Given
[tex]Digits = \{0,1,2,3,4,5,6,7,8,9\}[/tex]
Required
Number of digits between 0 ad 9999 that have one 1 and one 3
There are a total of 4 digits that make up any of the numbers in 0 to 9999 with the given condition
This can be represented as WXYZ
The remaining 8 digits will occupy the last 2 positions in the following ways:
So, the total number of selection is:
[tex]Total = 4 * (4 - 1) * 8 * 8[/tex]
[tex]Total = 4 * 3 * 8 * 8[/tex]
[tex]Total = 768[/tex]