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The Henry's law constant for helium gas in water at 30 ∘C is 3.7×10−4M/atm; the constant for N2 at 30 ∘C is 6.0×10−4M/atm.
a. If helium gas is present at 2.1 atm pressure, calculate the solubility of this gas.
b. If N2 is present at 2.1 atm pressure, calculate the solubility of this gas.

Respuesta :

dsdrajlin

Answer:

a. 7.8 × 10⁻⁴ M

b. 1.3 × 10⁻³ M

Explanation:

We can calculate the solubility of a gas using Henry's law.

S = k × P

where,

  • S: solubility of the gas
  • k: Henry's law constant
  • P: pressure of the gas

a. Determine the solubility of He

S = k × P

S = 3.7 × 10⁻⁴ M/atm × 2.1 atm

S = 7.8 × 10⁻⁴ M

a. Determine the solubility of N₂

S = k × P

S = 6.0 × 10⁻⁴ M/atm × 2.1 atm

S = 1.3 × 10⁻³ M

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