Answer:
Explanation:
Position of n the order fringe = n λ D / d
for n = 2
position = 2 λ D / d
λ = 710 nm , D = 1.1 m
d = .65 x 10⁻³
position 1 = 2 x 710 x 10⁻⁹ x 1.1 / .65 x 10⁻³
= 2403.07 x 10⁻⁶ m
= 2.403 x 10⁻³ m
= 2.403 mm .
For λ = 655 nm
position = 2 λ D / d
λ = 655 nm , D = 1.1 m
d = .65 x 10⁻³
position 2 = 2 x 655 x 10⁻⁹ x 1.1 / .65 x 10⁻³
= 2216.91 x 10⁻⁶ m
= 2.217 x 10⁻³ m
= 2.217 mm .
Difference between their position
= 2.403 - 2.217 = .186 mm .
