95 households have electricity bills of less than $200. Option C is correct.
Given that,
The monthly electric bills in a certain community are normally distributed, with a mean of $245 and a standard distribution of $55. There are 461 households in the community, how many of them have electric bills less than $200 is to be determined.
What is probability?
Probability can be defined as the ratio of favorable outcomes to the total number of events.
probability for the number of households has electric bills less than $200.
x = 200 , μ = 245 ; σ = 55
Now,
Probability,
z (p < 200) = [tex]\frac{X -\mu}{\sigma}[/tex]
z (p < 200) = (200 - 245)/55
= --45/5
= -0.818181
p < 200 = 0.206 (from z table)
Now, the number of households that has electricity bill less than $200,
= 461 * 0.206
= 94.966
≈ 95
Thus, 95 number of household have electricity bills of less than $200. Option C is correct.
Learn more about probability here:
brainly.com/question/14290572
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