Answer:
Equation of line in slope-intercept form is: y = -8x-39
Step-by-step explanation:
Given points are:
(-4, -7) and (-6, 9)
The slope-intercept form is given by the equation
[tex]y = mx+b[/tex]
Here m is the slope of the line and b is the y-intercept.
m is found using the formula
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
Here
(x1,y1) = (-4-7)
(x2,y2) = (-6,9)
Putting the values in the formula
[tex]m = \frac{9+7}{-6+4} = \frac{16}{-2} = -8[/tex]
Putting slope in general equation
[tex]y = -8x+b[/tex]
Putting (-6,9) in the equation
[tex]9 = -8(-6)+b\\9 = 48+b\\b = 9-48\\b = -39[/tex]
Putting the value of b we get
[tex]y = -8x-39[/tex]
Hence,
Equation of line in slope-intercept form is: y = -8x-39