contestada

A rollercoaster car has 2500 J of potential energy and 160 J of
kinetic energy at the top of the first hill.
How much energy and what kind of energy will there be at the
bottom of the first hill?
2660 J of KE
0 2660 J of Peg
2500 J of KE
160 J of PEG

Respuesta :

rafaleo84

Answer:

E_{k2}=2660 [J] kinetic energy.

Explanation:

The energy in the initial state i.e. when the rollercoaster is at the top is equal to the energy in the final state i.e. when it is at the bottom of the hill.

These states can be represented by means of the second equation.

[tex]E_{k1}+E_{p1}=E_{k2}\\160 + 2500 = E_{k2}\\E_{k2}=2660 [J][/tex]

Since the rollercoaster is located in the bottom of the hill where the potential energy level is zero, therefore there is only kinetic energy in the second state.

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