A 2.0-kg block starts from rest on the positive x axis 3.0 m from the origin and thereafter has an acceleration given by in m/s2. At the end of 2.0 s its angular momentum about the origin is:

A 2.0 kg block starts from rest on a positive x axis 3.0m from the origin and thereafter has an acceleration given by a= 4.0i - 3.0jin m/s2. At the end of 2.0 s, its angular momentum about the origin is ______.

answer : L = ( 2 kg ) [(-18m^2/s)k]

Explanation:

velocity vector(v) = (4.0i - 3.0j )(2.0s)

position vector(r) = ( 3.0m)i

determine the angular momentum about the origin

L = m ( r * v )

attached below is the detailed solution

okpalawalter8 okpalawalter8 · Answer 2 · 2021-12-31T11:06:09+01:00

Answer:

Angular momentum about the origin = [tex](-36kg.rad/s)k[/tex]

Explanation:

Given the acceleration,

[tex]v(t) = 4ti - 3tj[/tex]

So,

[tex]v(2) = 8i - 6j[/tex]

similarly,

[tex]x(t) = (3 + 2t^2) i - 1.5t^2 j[/tex]

so,

[tex]x(2) = 11i - 6j[/tex]

Angular momentum,

[tex]=mx(2)*v(2)\\\\=2*((-6x0-0x-6)i +(0x8-11x0)j +(11x-6--6x8)k)\\\\=2*(0i +0j -18k)\\\\=(-36kg.rad/s)k[/tex]

For more information on angular momentum, visit

https://brainly.com/subject/physics