The number of new houses that will be built is 200 while the profit is $13860000.
From the information given, the expected demand function will be:
= 60% × (300000 - 400Q) + 40% × (500000 - 275Q)
= 380000 - 350Q
Therefore, P = 380000 - 350Q
Since profit is the difference between the revenue and cost. This will be:
= (380000 - 350Q) × Q - (140000 + 240000Q)
Therefore, maximizing the profit will be:
380000 - 350 × 2Q - 240000 = Q
Q = 200
Therefore, profit will be:
= (380000 - 350Q) × Q - (140000 + 240000Q)
= (380000 - 350 × 200) × 200 - (140000 + 240000 × 200)
= 13,860,000
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